Question

solve (0,2pi]
sin x sin 2x + sin 2x =0

Answer 1

well factor out sin(2x)

so you have

sin(2x)(sin(x) + 1) = 0

so find where sin(2x) = 0

and also find where sin(x) + 1 = 0

for the given domain.

Answer 2

more explain plzz

Answer 3

ok... so just to check the question is

\[\sin(x)\sin(2x) + \sin(2x) = 0\]

you can factor out sin(2x)

and doing so you get

sin(2x)(sin(x) + 1) = 0

so the factors are sin(2x) and (sin(x) + 1)

if either factor is zero, then the equation is zero.

so find the values of x that make

sin(2x) = 0 and sin(x) + 1 = 0

does that make sense...?

Answer 4

yes it is
sinx=0
sin x = -1
right

Answer 5

no sin(2x) = 0...

so it means that the graph repeats 2twice over the domain of 2pi...

so where is sin(2x) = 0



and yes sin(x) = -1

what angle gives that value