You have a large amount of 8.00M stock solution. You need 1.60L of 2.50M solution for an experiment. How would you prepare the desired solution without wasting any stock solution? -Start with 1.60L of the stock solution. Add water until you reach a total volume of 5.12L . - Start with 1.60L of water. Add stock solution until you reach a total volume of 2.33L . -Start with 0.500L of the stock solution. Add water until you reach a total volume of 1.60L . -Mix 0.800L each of stock solution and water. I know how I would solve it, I think.. I would use M1VI=M2V2 but I don't understand the
..Question.
ur right :) use the equation from that u find the V and u dilute it and u get desired molarity of solution without throwing(wasting) any of the stock solution :)
So first I do the equation and find V2 right? How would I "dilute" it?
So I got V2= 500 ml or 0.5 L. What should I do now?
reach a total volume of 1.60L .
take V2 and dilute to 1.60L
I'm sorry I don't understand... Do I minus V2 from 1.6 to dilute it or how would I dilute it?
since u want to prepare 1.60 L of 2.5 M solution form 8 M siolution right
yes, so I used the formula and for V2=500 ml or 0.5 L
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