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simplify (sin x - cos x )^2
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Distribute: \[\LARGE (sinx-cosx)(sinx-cosx)\]
sin^2x-sinxcosx-cosc sinx +cos^2x
Correct.
Alright, now keep going
sin^2x+cos^2x
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yes, and what does that become?
1
Now combine the remaining terms
how
Well you have this left: \[\LARGE 1-sinxcosx-sinxcosx\]
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If it helps, think of the sinxcosx as x's
So: 1-x-x
:)
S what is your final annswer?
yes
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When we combine them, we get: 1-2sinxcosx, and 2sinxcos=sin(2x) So final answer: \[\LARGE 1-\sin(2x)\]
thank you so so much :)
Yup!
btw: \[\LARGE \mathbb{\color{#00FFCC}{WELCOME~TO~OPENSTUDY}} {\ddot\smile} \]
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