Question

If an equilateral triangle is circumscribe about a circle of radius 10 sq 3 cm, determine the side of the triangle.?

Answer 1

draw it out

Answer 2

can you draw it for me please

Answer 3

you knw OA = OB = \(10 \sqrt{3}\)
you're supposed to find AB

any guess how to approach this ? :)

Answer 4

wait =.=

Answer 5

I'd say the triangle area is the place to start

Answer 6

=.= I dont have any idea Im sorry

Answer 7

Yes, thats one way,
but there is a very easy way... if u knw 30-60-90 triangle properties or lil trig

Answer 8

I know the 30 60 90 rule :)

Answer 9

cool then its a piece of cake for u

Answer 10

If that is an equilateral triangle, then the altitude is sqroot(3) * (base/2)

Answer 11

@ganeshie8 for some reason its not more details on the drawing please =.=

Answer 12

lets wait for wolf to finish,
his method seems interesting :)

Answer 13

I erased it all.
I was trying to figure it out by the area formula.

Answer 14

we can find it by area formula

altitude = 10sqrt{3} + 10sqrt{3}/2 = 30sqrt(3)/2

Answer 15

I'm sorry to say my head isn't working =.= pls draw it =.=

Answer 16

altitude AD = OA + OD

= \(10 \sqrt{3} + \frac{10 \sqrt{3}}{2}\)

Answer 17

once u knw the altitude of equilateral triangle,
u should be able to find its side eh ?

Answer 18

alt = (side/2) * sqrt(3)

Answer 19

So,

\(\large 15\sqrt{3} = (side / 2) * \sqrt{3}\)

Answer 20

I hate to be the bearer of bad news but if we look at the OP once again:
If an equilateral triangle is circumscribe about a circle of radius 10 sq 3 cm, determine the side of the triangle.?
THhat would seem to mean that the triangle SURROUNDS the circle.
(see attached)

Answer 21

I agree lol we have been working the wrong problem :|