Ammonia gas is formed from nitrogen gas and hydrogen gas, according to the following equation, N2 (g) + 3H2 (g) arrow 2NH3 (g). If 140 grams of nitrogen gas is allowed to react with an excess of hydrogen gas to produce 155 grams of ammonia, what is the percent yield of this reaction?
A 45.5%
B 67.0%
C 82.4%
D 91.2%

Question

Ammonia gas is formed from nitrogen gas and hydrogen gas, according to the following equation, N2 (g) + 3H2 (g) arrow 2NH3 (g). If 140 grams of nitrogen gas is allowed to react with an excess of hydrogen gas to produce 155 grams of ammonia, what is the percent yield of this reaction?
A    45.5% 
B    67.0% 
C   82.4% 
D   91.2%

anonymous · Answer

Haber–Bosch process

anonymous · Answer

convert to moles, calculate theoretical moles formed using stiochiometry, then percent yield is (mass actual yield/ mass of theoretical yield) times 100