Question

If 10.1 of Fe are added to a solution of Copper (Cu) sulfate, how many grams of solid copper would form? 2Fe + 3CuSO4 -> FFe2(SO4)3 + 3Cu

Answer 1

\[10.1g Fe( \frac{ 1 Mole Fe }{ 55.85 g Fe })(\frac{ 3 moles Cu }{ 2 moles Fe })(\frac{ 63.55 g Cu }{ 1mole Cu })\]

how many moles Fe?
then we see 2 moles Fe makes 3 moles Cu
finally how many grams of Cu is that?

Answer 2

\[\frac{ 1925.565 }{ 111.7 }\]
\[= 17.238~\]

Answer 3

good job!!

Answer 4

thanks C: