Find the zeros of the polynomial function. f(x) = x3 + 5x2 - 4x - 20 A. x = -5, x = 4 B. x = -2, x = 2 C. x = -5, x = -2, x = 2 D. x = 5, x = -2, x = 2
Hint: x^3 + 5x^2 = x^2(x + 5) -4x - 20 = -4(x + 5)
B
Well, that was definitely a guess.
SORRY a
Yet another guess. I suppose my hint was not helpful enough for you
Trust me. Guessing is not the way.
OK Explain Please
ok
wow it disappeared
The best way to figure it out is to factor it. The best factoring method is "factor by grouping". With factor by grouping, you factor the first two terms x^2 + 5x^2, then then last two terms -4x - 20 When you factor each pair of terms you get: x^2(x + 5) and -4(x + 5) Notice that x + 5 is common to both factorizations. So then you factor out x + 5 to get (x + 5)(x^2 - 4) Now since x^2 - 4 is a difference of squares that factors to (x + 2)(x - 2) so the complete factorization of f(x) is f(x) = (x + 5)(x + 2)(x - 2) Then you set f(x) = 0 0 = (x + 5)(x + 2)(x - 2) And then set each factor equal to zero: 0 = x + 5 0 = x + 2 0 = x - 2 From there, you solve each for x.
x=5 x=2 x=2
x=-2 ast one
You did not solve for x.
i am confused
I find it strange that I have to do every single step for you.
0 = x + 5 Subtract 5 from both sides x = -5 0 = x + 2 Subtract 2 from both sides x = -2 0 = x - 2 Add 2 to both sides x = 2 So x = {-5, -2, 2}
i did the same but the opposite way i subtracted 0 from both sides
Thank you
You have to ask yourself if it makes sense to subtract 0 from both sides. What will subtracting zero from both sides accomplish? I don't know if you are joking or not.
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