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Simplify the expression. -5+i/2i Show all steps.
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\[\frac{-5+i}{2i}\] Multiplying numerator and denominator by i we find; \[\frac{-5+i}{2i} = \frac{-5+i}{2i} \times \frac{i}{i}\] \[= \frac{(-5+i) \times i}{2i \times i}= \frac{(-5i+i^2)}{2i^2}\] \[= \frac{(-5i+(-1))}{2(-1)}= \frac{-5i-1}{-2}= \frac{-(5i+1)}{-2}= \frac{1+5i}{2}\] \[= \frac{1}{2}+\frac{5}{2}i\] is the required simplified form. @Greenanole
Reason: \[i^2 = -1\]
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