find the integral value of k that makes 4x^2+4x-k a perfect square trinomial, and express the result in factored form.
@campbell_st
ok... so this uses the discriminant. For a perfect square the discriminant is equal to zero. so you would substitute a = 4, b = 4 and k then solve for k. does that make sense..?
would it be 4x^2+4x? if not then it doesn't make sense to me
ok... do you know what the discriminant is? its used to determine the type of roots that a quadratic will have..
so that will be what0?
if we square 4 we get 2
i mean root will be 16
well start with the basics. the discriminant comes for the general quadratic formula and is \[\Delta = b^2 - 4ac\] you need a perfect square so \[\Delta = 0..... or...... 0 = b^2 - 4ac\] in your problem you have a = 4, b = 4 and c = -k you need to substitute and solve for k.
0=b^2-16-k so far
k=b^2-16
not quite its \[0 = 4^2 - 4 \times 4 \times (-k)....... or..... 0 = 16 + 16k\]
i get k=-1
this correct?
thats what I get... which doesn't make a lot of sense as the quadratic isn't a perfect square with k = -1
oalright thanks for the help
glad to help...
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