find the integral value of k that makes 4x^2+4x-k a perfect square trinomial, and express the result in factored form.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@campbell_st
OpenStudy (campbell_st):
ok... so this uses the discriminant.
For a perfect square the discriminant is equal to zero.
so you would substitute a = 4, b = 4 and k
then solve for k.
does that make sense..?
OpenStudy (anonymous):
would it be 4x^2+4x? if not then it doesn't make sense to me
OpenStudy (campbell_st):
ok... do you know what the discriminant is?
its used to determine the type of roots that a quadratic will have..
OpenStudy (anonymous):
so that will be what0?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
if we square 4 we get 2
OpenStudy (anonymous):
i mean root will be 16
OpenStudy (campbell_st):
well start with the basics.
the discriminant comes for the general quadratic formula and is
\[\Delta = b^2 - 4ac\]
you need a perfect square so \[\Delta = 0..... or...... 0 = b^2 - 4ac\]
in your problem you have a = 4, b = 4 and c = -k
you need to substitute and solve for k.
OpenStudy (anonymous):
0=b^2-16-k so far
OpenStudy (anonymous):
k=b^2-16
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (campbell_st):
not quite its
\[0 = 4^2 - 4 \times 4 \times (-k)....... or..... 0 = 16 + 16k\]
OpenStudy (anonymous):
i get k=-1
OpenStudy (anonymous):
this correct?
OpenStudy (campbell_st):
thats what I get... which doesn't make a lot of sense as the quadratic isn't a perfect square with k = -1
OpenStudy (anonymous):
oalright thanks for the help
Still Need Help?
Join the QuestionCove community and study together with friends!