find six values of k such that x^2+kx+18 can be factored
the + sign on the last number means the factors will have the same sign (either both negative or both positive) the first step is list all pairs of numbers that multiply to give you 18 1,18 2,9 3,6 the sum of each pair gives a k if you make both numbers in each pair negative, you will get 3 more numbers for k
i have that so far
am i also supposed to multiply them
and add
to get 18
we know all those multiplied equal 18
if you multiply them, you get the last number (which is how I got them in the first place) the sum gives you the middle number.
for example k= 1+18= 19 x^2 + 19 x + 18 factors into (x+1)(x+18)
ok
what other numbers can k be?
it can be 11,9
so that's three found so far
the other "rule" is the + sign on 18 means the factors have the same sign you listed the plus factors. you could also have both factors be negative.
and then-9, and -11
and -19
yes and -19
thanks for the help
you should go over this problem, and maybe even multiply out the factors to see how it works. for example using k= -9 x^2 -9 x + 18 we used 3 and 6 (they multiply to get 18). the have a minus sign because + on the 18 means the same sign, and the - on the 9x means the largest factor is minus. if the largest factor is minus, and both are the same sign, both factors are minus -3 and -6 and we write (x-3)(x-6) multiply that out to get x^2 -3x-6x+18 = x^2 -9x +18
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