The spectrophotometer really measures the percent of light that is transmitted through the solution. The instrument then converts %T (transmittance) into absorbance by using the equation you determined in the prelab section. If the absorbance is 0.85, what is the percent light transmitted through the color sample at this collected wavelength?
How do find %T if .85 = -log(T). How do you get rid of -log?

Question

thomaster · Answer

$\LARGE 10^{-log(T)}$

that's how you get rid of it

thomaster · Answer

but you have to apply it on both sides.
So: $\Large 10^{-log(T)}=10^{0.85}$

anonymous · Answer

thank you!

abb0t · Answer

Wow, @thomaster you're really quite the smarty-pants.