Question

if 0.582 moles of zinc reacts with excess lead(IV) sulfate how many grams are zinc sulfate would be produced? can someone help me please?

Answer 1

So our equation is \[Zn + PbSO _{4} \rightarrow ZnSO _{4} + Pb \] balanced so everything is in a 1:1 ratio meaning moles of zinc before reaction is equal to moles of zinc sulcate after reaction . Then you just take mass= n x molar mass of \[ZnSO_{4}\] so 0.582 moles of ZnSO4 times its molar mass of 161.47 g/mol. Giving you 93.9755 = 93.98g of Zinc Sulfate

Answer 2

yeah thats correct bro thanks

Answer 3

No problem at all ^_^

Answer 4

can you help me with another problem do u have time?

Answer 5

Ya no problem I'm free right now

Answer 6

okay good . calculate the number of grams of oxygen required to convert 18.0 g of glucose to CO2 and H2O. C6h12(aq) + 6O2(g)----> 6CO2(g)+6H2O(I) so i need ___g O2 and _______ g CO2

Answer 7

@GavinxFiasco

Answer 8

glucose is C6H12O6

Answer 9

i hope u get it because i dont ? haha @GavinxFiasco

Answer 10

Ya I got it already so we first convert the amount of glucose we have from grams to moles
since \[n = mass/ molarmass \] we get 18g divided by 180.16g/mol(molar mass of glucose) and we get around 0.1 mol

Answer 11

Right approach: 1920g

Answer 12

oh okay got it so you divided 18 g by 180.16 okay so how many ____ g O2 would it be and how many of _____ g CO2?

Answer 13

@GavinxFiasco

Answer 14

Next we use our mol to mol ratio of glucose to carbon dioxide and water. Which give us 0.6 moles in both cases . . After we have the moles of each product we then apply the equation moles= mass/molarmass to get the mass of each product so for H20 we have \[0.6 \times 18.01 = 10.806 grams\] and for carbon dioxide we get \[0.6 \times 44.01 = 26.406 grams \]

Answer 15

@emanuelfarias is it right?

Answer 16

so 10.806 would be for g O2 AND for 26.406 for g CO2 RIGHT @GavinxFiasco

Answer 17

the top one was wrong? its not 10.806?the other one was correct

Answer 18

@abb0t Can u help me

Answer 19

@GavinxFiasco was helping me but 0.6*18.01 was wrong?

Answer 20

@aaronq calculate the number of grams of oxygen required to convert 18.0 g of glucose to CO2 and H2O. C6h12(aq) + 6O2(g)----> 6CO2(g)+6H2O(I) so i need ___g O2 and _______ g CO2

Answer 21

@GavinxFiasco

Answer 22

Oh I see it's because I looked for water not Oxygen my bad

Answer 23

oh its okay so would it be then

Answer 24

@GavinxFiasco so wat would ______ g O2?

Answer 25

@emanuelfarias we still have the same amount of moles then we just multiply it by molar mass of oxygen = 31.99886 which gives 19.1993g of oxygen

Answer 26

so 19.1993g thats the answer?

Answer 27

@GavinxFiasco

Answer 28

okay it was correct yay

Answer 29

you're welcome :)

Answer 30

Huh?