HELP ME PLEASE !! explain why it is not possible. f(-4) = 0, f(4) = 0, f is increasing on the interval -4 < x < 1, and decreasing everywhere else.
@tkhunny
@tkhunny please help
Not really seeing a problem with those parameters.
but do you know why they are not possible ?@tkhunny
@tkhunny
^^
i dont see n e thing wrong either
wait there is i think
how about this one f(3) = 6, f(5) = 0. f is decreasing for x < 0 and increasing for x > 0 @tkhunny @toolCoolChris
@toolCoolChris did you get it ?
how is f(5) increasing when its 0
f(x) , where x < 0 the function is dec. and f(x) x > 0 is increasing , so isn't contradicting where x =5 > 0
yet its 0 at that point
is that all ? @toolCoolChris
and can you help me with the first one @toolCoolChris ?
i guess thats all to it not much else being ask, if u tell me if the question or interval making any sense about the first one still thinking about it
okay so your still thinking about the first one?
i wonder if for the first one f(-4) and f(4) which are both at zero
sorry I dont know either
Please explore this function: \(f(x) = (x+4)^{2}(x-4)(x-16)\) This actually reveals the problem. It suggests you cannot accomplish the task with ANY even-degree polynomial.
thats all thats given @toolCoolChris
yet it mentions that out side from interval x= 3 to x= 1 its decreasing
i wonder if we can say as well that its suppose to be less then zero
@tkhunny Ohh I see
so the question really becomes can we count zero = as decreasing / or increasing
yeah it actually does :P
if we can then f(-3) = 1 and f(1) = 1 then yes there is nothing wrong because its decreasing... what does your book say if its possible or not?
it isnt possible because to get back to zero the fuction has to either decrease then increase or increase and decrease which makes that last statement false
true
|dw:1384316114224:dw|
Join our real-time social learning platform and learn together with your friends!