Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

HELP ME PLEASE !! explain why it is not possible. f(-4) = 0, f(4) = 0, f is increasing on the interval -4 < x < 1, and decreasing everywhere else.

OpenStudy (anonymous):

@tkhunny

OpenStudy (anonymous):

@tkhunny please help

OpenStudy (tkhunny):

Not really seeing a problem with those parameters.

OpenStudy (anonymous):

but do you know why they are not possible ?@tkhunny

OpenStudy (anonymous):

@tkhunny

OpenStudy (anonymous):

^^

OpenStudy (anonymous):

i dont see n e thing wrong either

OpenStudy (anonymous):

wait there is i think

OpenStudy (anonymous):

how about this one f(3) = 6, f(5) = 0. f is decreasing for x < 0 and increasing for x > 0 @tkhunny @toolCoolChris

OpenStudy (anonymous):

@toolCoolChris did you get it ?

OpenStudy (anonymous):

how is f(5) increasing when its 0

OpenStudy (anonymous):

f(x) , where x < 0 the function is dec. and f(x) x > 0 is increasing , so isn't contradicting where x =5 > 0

OpenStudy (anonymous):

yet its 0 at that point

OpenStudy (anonymous):

is that all ? @toolCoolChris

OpenStudy (anonymous):

and can you help me with the first one @toolCoolChris ?

OpenStudy (anonymous):

i guess thats all to it not much else being ask, if u tell me if the question or interval making any sense about the first one still thinking about it

OpenStudy (anonymous):

okay so your still thinking about the first one?

OpenStudy (anonymous):

i wonder if for the first one f(-4) and f(4) which are both at zero

OpenStudy (anonymous):

sorry I dont know either

OpenStudy (tkhunny):

Please explore this function: \(f(x) = (x+4)^{2}(x-4)(x-16)\) This actually reveals the problem. It suggests you cannot accomplish the task with ANY even-degree polynomial.

OpenStudy (anonymous):

thats all thats given @toolCoolChris

OpenStudy (anonymous):

yet it mentions that out side from interval x= 3 to x= 1 its decreasing

OpenStudy (anonymous):

i wonder if we can say as well that its suppose to be less then zero

OpenStudy (anonymous):

@tkhunny Ohh I see

OpenStudy (anonymous):

so the question really becomes can we count zero = as decreasing / or increasing

OpenStudy (anonymous):

yeah it actually does :P

OpenStudy (anonymous):

if we can then f(-3) = 1 and f(1) = 1 then yes there is nothing wrong because its decreasing... what does your book say if its possible or not?

OpenStudy (anonymous):

it isnt possible because to get back to zero the fuction has to either decrease then increase or increase and decrease which makes that last statement false

OpenStudy (anonymous):

true

OpenStudy (anonymous):

|dw:1384316114224:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!