Question

divide
(X+5)(X-3)/3(X+5) (by X+5)

Answer 1

You have a common X+5 term that can cancel out

Answer 2

isit x-3/3

Answer 3

I am a bit confused is your fraction this
\[\frac{(x+5)(x-3)}{3(x+5)}\] in the beginning?

Answer 4

yes, and they ask to divide by x+5

Answer 5

ok so the (X+5) term will drop out and then you will have

\[\frac{\frac{(x-3)}{3}}{(X+5)}\]

you can multiply by the reciprocal when you have a fraction within a fraction

\[\frac{(X-3)}{3}*\frac{(X+5)}{1}\]

Answer 6

-2x+5/3

Answer 7

You have to use FOIL to multiply the top terms (X-3)(X+5) ... the bottom term is correct

Answer 8

oh x^2+2x-15/3

Answer 9

yes

Answer 10

you can simply a little more and distribute the bottom 3 into each of the top terms numbers

Answer 11

x^2+2x-5

Answer 12

the whole top term is divided by 3 not just the -15

Answer 13

\[\frac{(x+5)(x-3)}{3(x+5)}\times \frac{1}{x+5}=\frac{x-3}{3(x+5)}\]

Answer 14

o yes my apologizes Mertsj is correct

Answer 15

no

Answer 16

x-3/3x+15

Answer 17

\[\frac{x-3}{3x+15}\]

Answer 18

NO!!!!!

Answer 19

Only factors may be cancelled.