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Mathematics 16 Online
OpenStudy (anonymous):

Quadrilateral OPQR is inscribed in circle N as shown below. What is the measure of ∠QRO? a. 40 b. 64 c. 116 d. 140

OpenStudy (anonymous):

OpenStudy (anonymous):

well u know the sum of any polygon is 360 degrees

OpenStudy (anonymous):

btw is angle QPO just x?

OpenStudy (anonymous):

if it is then just add all the angles together, set them equal to 360 solve for x, then plug in by into the function representing ∠QRO

Directrix (directrix):

Needed Theorem: If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral are supplementary. Angles R and P are supplementary but there is no variable measure given for <P. So, to get the value of x, solve this equation for x. m<O + m<Q = 180 x + 16 + 6x - 4 = 180 7x + 12 = 180 @lowcard2 what is the value of x?

OpenStudy (anonymous):

24?

Directrix (directrix):

Okay. If x = 24, m<R = 2*24 + 16. So, m<R = ? @lowcard2

OpenStudy (anonymous):

64

Directrix (directrix):

Okay. When you get m<R, recall that <R and <P are supplementary. So, m<P = 180 - m<R = 180 - 64 = ? @lowcard2

Directrix (directrix):

We're not finished.

OpenStudy (anonymous):

116

Directrix (directrix):

That is what I got.

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