Quadrilateral OPQR is inscribed in circle N as shown below. What is the measure of ∠QRO?
a. 40
b. 64
c. 116
d. 140
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OpenStudy (anonymous):
OpenStudy (anonymous):
well u know the sum of any polygon is 360 degrees
OpenStudy (anonymous):
btw is angle QPO just x?
OpenStudy (anonymous):
if it is then just add all the angles together, set them equal to 360 solve for x, then plug in by into the function representing ∠QRO
Directrix (directrix):
Needed Theorem: If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral are supplementary.
Angles R and P are supplementary but there is no variable measure given for <P.
So, to get the value of x, solve this equation for x.
m<O + m<Q = 180
x + 16 + 6x - 4 = 180
7x + 12 = 180
@lowcard2 what is the value of x?
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OpenStudy (anonymous):
24?
Directrix (directrix):
Okay.
If x = 24, m<R = 2*24 + 16.
So, m<R = ? @lowcard2
OpenStudy (anonymous):
64
Directrix (directrix):
Okay.
When you get m<R, recall that <R and <P are supplementary.
So, m<P = 180 - m<R = 180 - 64 = ? @lowcard2
Directrix (directrix):
We're not finished.
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