Quadrilateral OPQR is inscribed in circle N as shown below. What is the measure of ∠QRO? a. 40 b. 64 c. 116 d. 140
well u know the sum of any polygon is 360 degrees
btw is angle QPO just x?
if it is then just add all the angles together, set them equal to 360 solve for x, then plug in by into the function representing ∠QRO
Needed Theorem: If a quadrilateral is inscribed in a circle, then opposite angles of the quadrilateral are supplementary. Angles R and P are supplementary but there is no variable measure given for <P. So, to get the value of x, solve this equation for x. m<O + m<Q = 180 x + 16 + 6x - 4 = 180 7x + 12 = 180 @lowcard2 what is the value of x?
24?
Okay. If x = 24, m<R = 2*24 + 16. So, m<R = ? @lowcard2
64
Okay. When you get m<R, recall that <R and <P are supplementary. So, m<P = 180 - m<R = 180 - 64 = ? @lowcard2
We're not finished.
116
That is what I got.
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