How do I find bond order using the MO energy diagram ?
I know the equation is O=(n-n^*)/2 , but I keep getting the wrong answers. Can someone please help !
For ex. N2^+

Question

How do I find bond order using the MO energy diagram ? 
I know the equation is O=(n-n^*)/2 , but I keep getting the wrong answers. Can someone please help !
For ex. N2^+

aaronq · Answer

so you have 9 electrons..

$\dfrac{1}{2}(bonding-antibonding)$=$\dfrac{1}{2}(7-2)=\dfrac{5}{2}$

anonymous · Answer

Oh okay thanks @aaronq, I see how you got the answer, but what I'm having trouble understanding is how to find which are bonding and which are antibonding by looking at the diagram.

aaronq · Answer

They are labelled for nitrogen it's |dw:1384317458319:dw|

aaronq · Answer

the "*" denotes antibonding

anonymous · Answer

Oh okay makes a little more sense, thanks :D

aaronq · Answer

no problem !