Question

Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time (t), a=12, v(0)=7, s(0)=-1

Answer 1

what is it you want to solve for or find?

Answer 2

find the body's position at time t.

Answer 3

you want an equation that will tell you the position of where the body is by inputting time only, so use the kinematic equation:
s = s + vt + (1/2)at^2

Answer 4

they give you a=12 v(0)=7 s(0)=-1

Answer 5

right, so replace the terms in the equation with what was given to you

Answer 6

thank you so much

Answer 7

oh so do i get 6t^2+7t-1

Answer 8

so you have this equation:
s = s + vt + (1/2)at^2

a=12
v(0)=7
s(0)=-1

so it becomes,
s = -1 + 7t + (1/2)12t^2 which is
s = -1 + 7t + 6t^2 or
s = 6t^2 + 7t - 1
good work! ^_^

Answer 9

so i gotta question so if i have the same equation but my value of a=20 cos 3t v(0)=9 s(0)=5 so how do i work that out

Answer 10

How do i set it up

Answer 11

just plug it in, its the same thing

Answer 12

s = s + vt + (1/2)at^2

a=20 cos 3t
v(0)=9
s(0)=5

Answer 13

whats half of A=20 cos 3t

Answer 14

oh, the 1/2 only affects the 20, so its the same as saying
(1/2) * 20
the 1/2 wont affect the cos3t

Answer 15

so is it 10 cos 3t^3 +9t +5

Answer 16

did you get something else

Answer 17

(10)cos(3t)t^2 +9t +5, it should look like this, do you see how the 3t goes with the cos and the t^2 comes from the equation I gave you