Ask your own question, for FREE!
Chemistry 16 Online
OpenStudy (anonymous):

given the following chemical equation, determine how many grams of N2 are produced by 9.24 of H2O2 nd 6.56g of N2H4

OpenStudy (anonymous):

@GavinxFiasco

OpenStudy (anonymous):

Alright 3.80g should be your answer this time around

OpenStudy (anonymous):

it is incoorect u calculated the answer using N2H4 AS THE limiting reacting fewer moles og n2

OpenStudy (anonymous):

yay is right now:)

OpenStudy (anonymous):

Ya H2O2 was the limiting reagent

OpenStudy (anonymous):

You're welcome once again

OpenStudy (anonymous):

omg dude ur bad retrice

OpenStudy (anonymous):

@GavinxFiasco IN the following reactiong, 451.4 g of lead reacts with excess oxygen forming 337.4 g lead(II) oxide.calculate the percent yield of the reaction

OpenStudy (anonymous):

Hope you understand this a little better as well . Look for limiting reagent than solve

OpenStudy (anonymous):

i wiil okay

OpenStudy (anonymous):

2Pb(s)+O2(g)----> 2PbO(s) @GavinxFiasco

OpenStudy (anonymous):

@emanuelfarias that's our balance equation

OpenStudy (anonymous):

yeah its a different problem

OpenStudy (anonymous):

69.39 % is the answer

OpenStudy (anonymous):

@GavinxFiasco

OpenStudy (anonymous):

@emanuelfarias 69.39% is the answer

OpenStudy (anonymous):

thanks:)

OpenStudy (anonymous):

just like every other problem get moles . Use mole ratio to find mole of product use the moles found to find grams ( mass = moles x molar mass) Then take how many grams you actually got 337.4g and divide it by your theoretical mass 486.25 x 100 to get a percent

OpenStudy (anonymous):

You're welcome once again

OpenStudy (anonymous):

@GavinxFiasco assume 0.160 mol of N2 and 0.527 mol of H2 are present initially? questions after the complete reactions how many moles of ammonia are produced?

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

can u help me solve this one plz

OpenStudy (anonymous):

0.32 mol of NH3

OpenStudy (anonymous):

@emanuelfarias

OpenStudy (anonymous):

okay now it was how many moles of H2 remain and how many moles of N2 remain?

OpenStudy (anonymous):

@GavinxFiasco

OpenStudy (anonymous):

0.160 mol N2 , 0.047 mol H2

OpenStudy (anonymous):

0 mol of N2 is reaction goes to completetion though

OpenStudy (anonymous):

so o.160 mol n2 and 0.047 for h2 right?

OpenStudy (anonymous):

the N2 is not 0.160 wat is it?

OpenStudy (anonymous):

@GavinxFiasco

OpenStudy (anonymous):

it would be 0 remains

OpenStudy (anonymous):

@emanuelfarias

OpenStudy (anonymous):

@k it work?

OpenStudy (anonymous):

@GavinxFiasco assume that 4 molecules of nitrogen and 9 molecules of hydrogen are present? after complete reaction, how many molecules of ammonia are proceded?

OpenStudy (anonymous):

@GavinxFiasco N2(g)+3H2(g)----> 2NH3(g)

OpenStudy (anonymous):

im so confused on this one?

OpenStudy (anonymous):

@GavinxFiasco

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!