find the interior angles of the triangle whose sides are 12cm,15cm,22cm. WITH MEDAL
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OpenStudy (anonymous):
Do you know how to start?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Have you heard of the Cosine Rule?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
It's sort of similar to the Pythagorean theorem but it works for all triangles.
\[a^2 = b^2 +c^2 - 2(b)(c)\cos(\alpha)\]
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OpenStudy (anonymous):
|dw:1384341672271:dw|
OpenStudy (anonymous):
So just plug those numbers into your calculator and solve.
OpenStudy (anonymous):
wait so the answer is
OpenStudy (anonymous):
its veryv hard :(
OpenStudy (anonymous):
It's ok, you can do it...
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OpenStudy (anonymous):
teach me step by step
OpenStudy (anonymous):
Did you try plugging in those numbers into the formula I gave you?
OpenStudy (anonymous):
yes
12^2=15^2+22^2-2(15)(22) cos
OpenStudy (anonymous):
ok, now multiply those out
OpenStudy (anonymous):
144=225+484-660 cos
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OpenStudy (anonymous):
144 = 225 + 484 - 660 cos(A)
Now, simplify the expression so that you have "cos(A)" on one side and everything else on the other side.
OpenStudy (anonymous):
144=49cosA?
OpenStudy (anonymous):
No, more like this:
\[\frac{ 144 -225 - 484 }{ -660 } = \cos(A) \]
OpenStudy (anonymous):
And then calculate the left side . . .
OpenStudy (anonymous):
+484
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OpenStudy (anonymous):
What do you mean?
OpenStudy (anonymous):
144-225+484 over -660 =cosA
OpenStudy (anonymous):
No, because you are subtracting "225" AND "484" from both sides... Thus, the numerator should be "144 - 225 - 484"
OpenStudy (anonymous):
So, you are subtracting 225 from both sides and you are subtracting 484 from both sides.
OpenStudy (anonymous):
ok :)
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OpenStudy (anonymous):
so the answer is 30.68
OpenStudy (anonymous):
You mean the angle?
OpenStudy (anonymous):
thats my final answer 30.68
OpenStudy (anonymous):
You mean the size of the angle in degrees?
OpenStudy (anonymous):
It's about that--I calculated that it was about 31.123 degrees... And remember, that's for angle A, the angle across from side "a", which we're assuming has length of 12 cm.
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OpenStudy (anonymous):
Anyway, you continue the same process with another side like so:
\[b^2 = a^2 + c^2 -2(a)(c)\cos(B)\]
And then, when you have angle A & angle B, you can easily figure out the size of angle C because:
C = 180 - A - B
OpenStudy (anonymous):
Make sense?
OpenStudy (anonymous):
@Splash_Dance how
OpenStudy (anonymous):
What?
OpenStudy (anonymous):
Splash_Dance
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OpenStudy (anonymous):
Yes...
OpenStudy (anonymous):
interior angle?
OpenStudy (anonymous):
can i use herons law?
OpenStudy (anonymous):
No, that's for calculating the Area of a triangle--you're just looking for the angles.