find the zeros of the polynomial and state the multiplicity: f(x)=x^3-x^2-4x+4
How do you find the possible rational zeros?
that's what I don't understand :/
Can you answer these questions? Find the factors of the constant term. Find the factors of the coefficient of the term with the highest exponent.
Find the factors of the constant term means find the factors of 4 since 4 is the constant term. So what are the factors of 4?
1, 2, and 4?
well plus or minus but okay. Now what are the factors of the coefficient of the term with the highest exponent. This means I'm looking at 1 since 1 is in front of x^3. What are the factors of 1?
1
well plus or minus but yeah
oh okay so +/- 1
We define the possible rational zeros as the set containing the factors of the constant term/ the factors of the coefficient of the term with highest exponent. So this means we have \[\text{ possible rational zeros } = \{ {\frac{\pm 1}{\pm 1} , \frac{\pm 2}{\pm 1}, \frac{\pm 4}{\pm 1} }\}\]
or just simply \[\{ \pm 1 , \pm 2 , \pm 4\} \]
Now possible doesn't mean actual.
This just narrows are search.
So we have f(x)=x^3-x^2-4x+4 . We try some of our possible rational zeros to see which gives us 0.
What value in our possible rational set do you want to try and see if it works?
would we do 1 since it is first?
You can but I was asking you where you want to start.
So if we plug in 1 do we get 0?
am I plugging 1 in for x?
We are trying to find for what values of x is f zero so yes.
okay by plugging 1 in for x it does equal 0
\[f(1)=1^3-1^2-4(1)+4 \] is this zero? You are right the answer is yes. x=1 is a zero since f will be 0 when x=1 If x=1 is a zero then x-1 is a factor of f. Now divide f by x-1. You may use synthetic or long polynomial division.
what would my equation be for that? do I just plug in x-1?
for f?
like you are dividing f by x-1 to find the other factors of f.
remember f is x^3-x^2-4x+4
f/(x-1)=?
\[\frac{x^3-x^2-4x+4}{x-1} =?\]
\[0+ \frac{ 4x }{ x-1 }\]
No that is way off. I'm sorry.
Do you know how to do long division with polynomials?
I just don't understand how to do this I suppose
Have you discussed long division? I could show you an easier way but doesn't always work out so well like polynomial division does.
I tried to do the problem in synthetic division but it just said it's not possible
it is possible
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