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Mathematics 21 Online
OpenStudy (anonymous):

Verify (1-sin^2x over cosx= cosx) as a trig identity

OpenStudy (solomonzelman):

DO you have to use another identity to do this, or a triangle?

OpenStudy (anonymous):

It doesn't say but I think it's another identity

OpenStudy (solomonzelman):

1-sin^2x over cosx= cosx since sin^2x+cos^2x=1, therefore we an imply that (if we subtract sin^2x from both sides) sin^2x+cos^2x=1 sin^2x+cos^2x+sin^2x-sin^2x=1-sin^2x cos^2x=1-sin^2x Now substitute, cos^2x=1 for 1-sin^2x 1-sin^2x over cosx ---> cos^2x over cosx cos^2x over cosx divide top and bottom by cosx cosx=cosx

OpenStudy (anonymous):

Thank you

OpenStudy (solomonzelman):

Anytime! (Took this last year.)

OpenStudy (anonymous):

It's killin me lol

OpenStudy (solomonzelman):

If you need more help, I can try....

OpenStudy (anonymous):

Ok thank you

OpenStudy (solomonzelman):

Anytime!

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