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Mathematics
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Verify (1-sin^2x over cosx= cosx) as a trig identity
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DO you have to use another identity to do this, or a triangle?
It doesn't say but I think it's another identity
1-sin^2x over cosx= cosx since sin^2x+cos^2x=1, therefore we an imply that (if we subtract sin^2x from both sides) sin^2x+cos^2x=1 sin^2x+cos^2x+sin^2x-sin^2x=1-sin^2x cos^2x=1-sin^2x Now substitute, cos^2x=1 for 1-sin^2x 1-sin^2x over cosx ---> cos^2x over cosx cos^2x over cosx divide top and bottom by cosx cosx=cosx
Thank you
Anytime! (Took this last year.)
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It's killin me lol
If you need more help, I can try....
Ok thank you
Anytime!
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