PreCalculus help please!
How do I transform this equation from polynomial form to vertex form by completing the square?!
f(x)=x^2-8x=21
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (*insert name here*):
You got the first step down, now do:
\[\LARGE (\frac{b}{2})^2\]
OpenStudy (anonymous):
see your question please.
OpenStudy (anonymous):
Okay, so I get 16?
OpenStudy (anonymous):
if the eq is \[x ^{2}+ax=b,then add \left( \frac{ a }{ 2 } \right)^{2} \to both sides.\]
OpenStudy (*insert name here*):
I'm gonna wait and see what @surjithayer has to say
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (*insert name here*):
So once you get 16, just like surj is showing, you add it to both sides so:
\[\LARGE (x^2-8x+16)=21+16\]
Now put it in:
\[\LARGE (x \pm b)^2=c\]
OpenStudy (anonymous):
\[\left( x-4 \right)^{2}=37\]
OpenStudy (*insert name here*):
@surjithayer maybe we should let her do the work >.>
OpenStudy (anonymous):
Alright! Thank you guys, I think I get it now. I appreciate it!
And I'm going over the work anyway @*Insert Name Here* , so don't worry.
Thanks again! ♥