PreCalculus help please! How do I transform this equation from polynomial form to vertex form by completing the square?! f(x)=x^2-8x=21
You got the first step down, now do: \[\LARGE (\frac{b}{2})^2\]
see your question please.
Okay, so I get 16?
if the eq is \[x ^{2}+ax=b,then add \left( \frac{ a }{ 2 } \right)^{2} \to both sides.\]
I'm gonna wait and see what @surjithayer has to say
So once you get 16, just like surj is showing, you add it to both sides so: \[\LARGE (x^2-8x+16)=21+16\] Now put it in: \[\LARGE (x \pm b)^2=c\]
\[\left( x-4 \right)^{2}=37\]
@surjithayer maybe we should let her do the work >.>
Alright! Thank you guys, I think I get it now. I appreciate it! And I'm going over the work anyway @*Insert Name Here* , so don't worry. Thanks again! ♥
Alright, good luck!
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