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Mathematics 9 Online
OpenStudy (anonymous):

If this is the graph of f(x), then which of the attached graphs could be the graph of f^-1(x)?

OpenStudy (anonymous):

OpenStudy (anonymous):

A & B

OpenStudy (anonymous):

C & D

undeadknight26 (undeadknight26):

I just learned this but i forgot it...

undeadknight26 (undeadknight26):

@ash2326 @helppls123 come please...

undeadknight26 (undeadknight26):

man i hate when this happens because i wanna know to :]

OpenStudy (anonymous):

@ranga do you think i could gget some help with this please?

OpenStudy (ranga):

For one-on-one function, f(x) and f-1(x) will be a reflection on the line y = x. y =x is a 45 degree straight line that passes through the origin.

OpenStudy (anonymous):

would it be A or B then?

OpenStudy (ranga):

B

OpenStudy (ranga):

When reflecting over the line y = x, the coordinates will shift places: (x,y) on reflection will become (y,x). So take a few convenient points in the original f(x). Switch coordinates and see if they line of any of the curves in the choices.

OpenStudy (anonymous):

thank you SO much :)

OpenStudy (anonymous):

can you help me with this graph? graphs are just so confusing to me D:

OpenStudy (anonymous):

OpenStudy (ranga):

You will notice the graph has a vertical asymptote at x = 3. Which choices gives vertical vertical asymptote at x = 3?

OpenStudy (anonymous):

I'm thinking A and D?

OpenStudy (ranga):

Vertical asymptote at x = 3 means, if I put x = 3, y will be negative or positive infinity. Which one goes to infinity at x = 0. Remember log(x) or ln(x) is defined only for x > 0. At x = 0, ln(x) or log(x) will be negative infinity.

OpenStudy (anonymous):

would it be C then? because the -3 would give a vertical asymptote of 3?

OpenStudy (ranga):

Yes C. At x = 3, we have ln(0) (equal to -infinity) which means a vertical asymptote at x = 3.

OpenStudy (anonymous):

thank you!!! :)

OpenStudy (ranga):

you are welcome.

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