Question

x+2 + (x-1)(x+2)
--------- ----------
(x-3)(x+1) x-3
simplify the sum.

Answer 1

ok... so you are being asked to add 2 fractions.... so the same rules apply for numeric factions apply.

1. you need a common denominator

which appears to be

(x -3)(x + 1)

so the 2nd fraction needs (x+1) in the numerator and denominator

so you have

\[\frac{(x +2)}{(x -3)(x +1)} + \frac{(x -1)(x +2)(x +1)}{(x -3)(x + 1)}\]

so you can write it as

\[\frac{(x +2)(1 + (x-1)(x+1))}{(x -3)(x +1)}\]

I'll let you simplify ti further.

Answer 2

I ended up getting...
\[\frac{ x ^{3}+2x ^{2} }{ (x-3)(x+1) }\]
i told you i am bad at this...

Answer 3

yep. that looks good, you may need to just distribute the denominator...

I'm not sure what form you answer needs to be in.

Answer 4

you leave the denominator as is!
thank you so much, HUGE HELP!