What is the spring constant for the spring in the graph?
Will give medal! See my reply post for graph!

Question

anonymous · Answer

See attached file for graph.

anonymous · Answer

im not sure how to do this but I will try to get someone over here to help you :))

anonymous · Answer

@myininaya @AllTehMaffs @amistre64

anonymous · Answer

So, if this were just a line, what would its basic equation of a line look like 

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?

anonymous · Answer

umm I'm not really sure but I think it would be the slope and for the question I asked I think it would be 25.0 N/m not sure though

anonymous · Answer

or +0.04 N/m

anonymous · Answer

^_^ 

The equation of this line would fit 
$$ y=mx+b$$

So looking at your graph, just replace these variables with force for y and distance for x giving you

$$F=-kx$$
which is Hooke's law.  And you're correct in that the slope would be the slope of the line. 

$$ -k=\frac{\Delta y}{\Delta x}=\frac{-.5N}{.02m}$$ 
$$k=25 \ N/m$$

anonymous · Answer

~the spring constant would be the slope of the line

anonymous · Answer

oh ok got it thanks!

anonymous · Answer

Welcome ^_^

anonymous · Answer

can u help me with one more question?

anonymous · Answer

yah yah

anonymous · Answer

What is the period of the spring's motion in the position-time graph shown here?

anonymous · Answer

is it 2.0 s?

anonymous · Answer

The period of a function like that is from one crest to the next

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