A(n) = 12 + (n - 1)(-4)
Find the third, sixth, and twentieth terms of the sequence described by the following rule. Be sure to show all of your work.
start with A(n) = 12 + (n - 1)(-4) for the third term, replace n with 3 can you write down what you get ?
Everywhere you see "n", erase it, and put in 3 instead
Got it ;) Thank you so much! @phi
Wait then what do I do with A?? @phi
And what do I do for the sixth and twentieth terms? Do I replace the sixth with 6 and twentieth with 20?
A(n) is just a "name" for a term A(3) is the third term you do not need it.
Do I replace the sixth with 6 and twentieth with 20? Exactly. the formula tells you how to find any term you want.
And so the sixth term would be A(6) and the twentieth would be A(20) correct??
yes, but those are the names. they want the actual number, so for example A(6) = 12+(6-1)(-4) now simplify the right side
The right side would be -8... So do I multiply that by 6? Or is -8 the answer?
yes, A(6) = -8 that says " the sixth term is -8" -8 is the answer. But I would write A(6)=-8 to make it clear.
Okay I got it! Thank you very much for your help!
btw, A(n) does not mean A times n . It is just a way to say the nth term of A you have to get used to this way of writing things. Algebra mostly sticks to rules, but there are these strange conventions you have to memorize.
Okay! Got it! Thank you for your time! :))
sometimes you see it this way \[ A_n\] which means the same thing, the nth term of A
So no multiplication between the two... Got it. Thanks.
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