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Mathematics 9 Online
OpenStudy (anonymous):

A(n) = 12 + (n - 1)(-4)

OpenStudy (anonymous):

Find the third, sixth, and twentieth terms of the sequence described by the following rule. Be sure to show all of your work.

OpenStudy (phi):

start with A(n) = 12 + (n - 1)(-4) for the third term, replace n with 3 can you write down what you get ?

OpenStudy (phi):

Everywhere you see "n", erase it, and put in 3 instead

OpenStudy (anonymous):

Got it ;) Thank you so much! @phi

OpenStudy (anonymous):

Wait then what do I do with A?? @phi

OpenStudy (anonymous):

And what do I do for the sixth and twentieth terms? Do I replace the sixth with 6 and twentieth with 20?

OpenStudy (phi):

A(n) is just a "name" for a term A(3) is the third term you do not need it.

OpenStudy (phi):

Do I replace the sixth with 6 and twentieth with 20? Exactly. the formula tells you how to find any term you want.

OpenStudy (anonymous):

And so the sixth term would be A(6) and the twentieth would be A(20) correct??

OpenStudy (phi):

yes, but those are the names. they want the actual number, so for example A(6) = 12+(6-1)(-4) now simplify the right side

OpenStudy (anonymous):

The right side would be -8... So do I multiply that by 6? Or is -8 the answer?

OpenStudy (phi):

yes, A(6) = -8 that says " the sixth term is -8" -8 is the answer. But I would write A(6)=-8 to make it clear.

OpenStudy (anonymous):

Okay I got it! Thank you very much for your help!

OpenStudy (phi):

btw, A(n) does not mean A times n . It is just a way to say the nth term of A you have to get used to this way of writing things. Algebra mostly sticks to rules, but there are these strange conventions you have to memorize.

OpenStudy (anonymous):

Okay! Got it! Thank you for your time! :))

OpenStudy (phi):

sometimes you see it this way \[ A_n\] which means the same thing, the nth term of A

OpenStudy (anonymous):

So no multiplication between the two... Got it. Thanks.

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