Question

can some one help me. on this math problem
thank you!!

Given f(x) = the quantity of 4x plus 1, divided by 3 solve for f-1(3).

Answer 1

how would you get the inverse of \[y = \frac{ 4x+1 }{ 3 }\]

Answer 2

here's a hint on how to get started on finding the inverse\[x = \frac{ 4y+1 }{ 3 }\]

Answer 3

well probably change were is 3 you put it on were is 4 will be like x=(3y+1) /4

Answer 4

You just solve for y as you would for any equation only this y is for f-1(x) and not f(x)
if you multiply both sides by 3 and are still solving for y:\[3x = 4y+1\]

Answer 5

so I subtract 4 to both sides

Answer 6

how can you subtract 4? "4y" is the whole term.
you can subtract 4y but we don't want to do that. We want to get y alone.

however if we subtract 1\[4y=3x-1\]

Answer 7

so then I should divide by 4 to live the y alone.

Answer 8

yeah and that is the formula for f-1(x)

Answer 9

ok so which of this will be the answer
A) 2
B)4
C)6
D)8

Answer 10

so the D will be the answers

Answer 11

I don't know. Why don't you plug in 3 into \[f^-1(x) = \frac{ 3x-1 }{ 4 }\]

Answer 12

so it will be A can you check that out please!

Answer 13

yeah that's right

Answer 14

thank you!
i just want to be sure