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Mathematics 16 Online
OpenStudy (anonymous):

What is a solution

OpenStudy (anonymous):

x2-6x = -10 -4x = -10 x= 10/4 x= 5/2

OpenStudy (anonymous):

im sorry the quadratic formula is used

OpenStudy (anonymous):

that is x^2 not 2x right?

OpenStudy (anonymous):

These are "2" the choices x = -3 - i x = 3 + i

OpenStudy (anonymous):

\[x=3+i \sqrt{19}\] or \[x=-3-i \sqrt{19}\]

OpenStudy (anonymous):

So move everything to the left hand side: \[x^2 - 6x + 10 = 0\] Solve the quadratic equation by completing the square: \[x^2 - 6x = -10\] Take one half of the coefficient of x and square it, then add it to both sides. \[x^2 - 6x + 9 = -1\] Factor the left hand side: \[(x-3)^2 = -1\] Eliminate the exponent on the left hand side. \[x - 3 = i, x-3 = -i\] Look at the first equation: Solve for x. \[x = 3 + i or x-3 = -i\] Look at the second equation: Solve for x. \[x = 3+i, x = 3-i\]

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

So the solution is x = 3 + i or x = 3 - i

OpenStudy (anonymous):

i understand it completly

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