Help solving this problem please, sort of have an answer. x,y = (-3/2, 1) I got this answer but problem claims there is two. What have I overlooked?
I solved by substitution for the equations xy = 6 and 9x - y + 53 = 0 I isolated the y and got y = 9x + 53 then I plug it into the xy = 6 to get x ( 9x + 53 ) = 6 use the distributive property so 9x^2 + 53x - 6 = 0 then you would factor (9x - 1)(x + 6) = 0 solve for x when 9x - 1 = 0 and x + 6 = 0 you get to x values then you plug each back into one of the given equations to get your y values :)
got 1/9, 54 -6, -1
yep :)
how would i find the y values if given something like: 5y(y-4)
you mean 5y(y-4) = 0 ? then solve for 5y = 0 and y - 4 = 0
So 0 and -4 as Y values? How would you start the substitution if it was y = x^2-8 y = 2x -5 Sorry for all the questions but trying to get all the different way in my head lol.
y = x^2-8 y = 2x -5 so x^2 - 8 = 2x - 5
ah ok makes sence thank you so much
glad I could help :D
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