Question

What are the solutions?
1/2x^2+2x+3=0

Answer 1

Well we could use quadratic formula.

Using\[ax^2+bx+c\]
as a format, a = .5, b=2, and c=3.

\[-b \pm \sqrt{\frac{ b^2-4ac }{ 2a }}\]
\[-2 \pm \sqrt{\frac{ 2^2-4(1/2)(3) }{ 2(1/2) }}\]
\[-2 \pm \sqrt{\frac{ -2 }{ 1 }}\]
So,
it would be\[x=-2-\sqrt{-2}\]
and
\[-2+\sqrt{-2}\]
If you feel like simplifying it a little more, we could use the imaginary number i (which equals the square root of -1)
and then your solutions would be \[x=-2-2i\]
or
\[x=-2+2i\]

Answer 2

i agree with @halorazer ...

Answer 3

Great explanation for me too

Answer 4

I aim to please. ^_^