Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

In July a paleontologist found 368 fossils at a dig. In August, she found about 14 fossils per day. Is the number of fossils the paleontologist found in August proportional to the number of days she spent looking for fossils that month ?

OpenStudy (anonymous):

No, it is not. The direct variation formula is y=kx Where k is the variation. Because she found 368 fossils, that would be y. The amount of fossils she finds per day would be 14, and that would be k. There are 31 days in august, so when you put in 14(31) you get 434, which is not true. The only thing that doesn't make sense to me is that it says she found 368 in July, and she was finding 14 a day in August. These two numbers are pretty much unrelated I believe.

OpenStudy (anonymous):

Thanks a lot

OpenStudy (anonymous):

actually ,WRONG

OpenStudy (anonymous):

Can you not

OpenStudy (anonymous):

its yes using the invert theory y=xy when the variations are solved the 368 would be proportional due to the no disclosed array

OpenStudy (anonymous):

*non

OpenStudy (anonymous):

Thanks beatz

OpenStudy (anonymous):

halorazer was right if you were using this related to formulas, Apple bite, what class is this for, and are you using formulas

OpenStudy (anonymous):

cuz halorazer would be right if your doing an actually formula or if your just using real life equations or not

OpenStudy (anonymous):

Like I said, they seem to be unrelated considering that she found 368 in July, and then it goes on to talk about how she started to find 14 per day in August. Like seriously how do I know she wasn't just slacking in August or something. O.o

OpenStudy (anonymous):

Well this is a question i got from school and well its about proportional and non proportional relationships

OpenStudy (anonymous):

haha i feel like this question isn't complete

OpenStudy (anonymous):

is it from a math class? If so what type of math class, Algebra, Geometry, Algebra 2, pre calc (I'm in pre calc, ugg 9th grade is hard)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!