Question

A game plan to use a variation of the Tarot deck for character creation. The idea is to have a card randomly selected for each of the 6 character traits, and assigning a score and special trait based on the card selected. If the game only uses 22 cards Major Arcana, how many different characters can be created?

Answer 1

do you have ur combination and permutation equations?

Answer 2

This seems to be like a very difficult problem to me.

Answer 3

not yet

Answer 4

I have trying to figure out how to set that up DemolisionWolf

Answer 5

its been a while since i've done these so give me a min. and if anyone else remembers, fell free to post ^_^

Answer 6

Alright I will read over the question again to see if I understand it more.

Answer 7

are the cards placed back in the deck after the character has been made, or are the cards left out after each character is made?

Answer 8

I believe the cards are left out

Answer 9

On my assignment it says the answer is really big

Answer 10

if the cards are left out then
at the end of character 1, we would have 22-6 cards remaing = 16
at the end of character 2, we would have 16-6=10 cards remaining
at the end of character 3, we would have 10-6=4 cards remaining.
so taking that route would leave us 3 characters created.

If the cards are put back in then..

Answer 11

oh does it? ok, then I think I know what to do,

we have to use an exponenet-

Answer 12

ok

Answer 13

since you haven't learned about combinations and permutations, then this is the equation you want to use:
\[NumberOfCards^{NumberOfTraits} = TotalPossibleCharacters\]

Answer 14

I have learned about permutations just not good at them

Answer 15

ok

Answer 16

I like the formula you came up with

Answer 17

haha, so that is the permutation formula, it figures out all the possible ways that 22 cards can be ordered into groups of 6.

so did you have 22^6 as your equation?

Answer 18

No I am still trying to come up with my equation

Answer 19

How did you come up with that equation

Answer 20

are u there still

Answer 21

so the equation is nothing special, it is just a way to say how many possible ways there are to organize 22 cards in groups of 6 cards.

\[n^r\]
where r is the number of 'slots' that are possible and
n is the number of total options available.

for example, if we had a combination lock, and it had one dial on it and the dial goes from 0 to 9, then, the number of 'slots' would be 1, becuause there is only one time we can have a number. and the number of 'options' would be 10, becuase we go from 0 to 9. so the equation would look like:
10^1 = 10, which is total number of possible combinations to have the lock set to. which makes sense to you and me. imagine a combination lock that only has an option to be 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. then there are 10 total ways possible.

I hope this helps
I have to go now

Answer 22

10 is the answer

Answer 23

the answer to your question is 10? hmm...

Answer 24

no I was asking you what you got in the example

Answer 25

oh ok. ya, 10 is what it would be in the example.

Answer 26

How would I get the answer in my problem?

Answer 27

\[22^6\]

Answer 28

Yeah that what I already have the answer for that problem