Question

Which function could produce the attached graph?

A. f(x)=4e^-0.05x
B. f(x)=4e^0.5x
C. f(x)=4e^0.05x
D. f(x)=4e^-0.5x

Answer 1

its decaying, so you know it must be a negative exponent on the e

Answer 2

so just plug in an X value to solve for y to determine if it is 0.5 or 0.05

Answer 3

it looks like it is 0.05, so A

Answer 4

thank you! :)

Answer 5

y = Ae^(Bx) is the general exponential formula
when x = 0, y = 4 from the graph
4 = A(1) so A = 4
y = 4e^(Bx)
Here it is an exponential decay. So B must be negative.

The curve fall from y value of 4 to 2 when x is approx. 15.
So the approx half-life is 15

The formula for half life is: t_half = ln(2) / B. So B = ln(2) / 15
B = approx 0.05 and put a negative in front because of decay.

y = 4e^(-0.05x)