Question

Derive the limit using L'Hopital's Rule.

Answer 1

\[\lim_{x \rightarrow \frac{ \pi }{ 2 }^{+}}\frac{ cosx }{ 1-sinx }\]

Answer 2

\[\lim_{x \rightarrow \frac{ \pi }{ 2 }^+}\frac{ sinx }{ cosx }\]

Answer 3

I got stuck on this part.

Answer 4

sin/cos=tan

Answer 5

yea, but then what would it be?

Answer 6

if i were to plug pi/2 in tan then it would become 1/0.

Answer 7

can you sketch a graph of tan x,

then look for the value you get when x=(π/2)^+

Answer 8

Oh, ic