Question

Need help with a lollipop problem >.<
i'll post it up in a bit.
Please and Thank you

Answer 1

here you go

Answer 2

ignore the picture on the right

Answer 3

V = 4/3(pi)r^3
Take derivative with respect to time t
dV/dt = 4/3(pi)(3r^2)dr/dt = 4(pi)r^2dr/dt
Just for visualization you can think of the sphere as made up of liquid and each lick subtract the same few drops of water. So dV/dt can be assumed to be a constant.
K = 4(pi)r^2dr/dt
dr/dt = K / ((4(pi)r^2) = C / r^2

The rate of decrease in radius is inversely proportional to the square of the radius.

So when radius is high, dr/dt will be small.

When radius is small, dr/dt will be pretty high.

Answer 4

our teacher said it was constant

Answer 5

@razor99

Answer 6

yep

Answer 7

@razor99
the kids are right, right ?

Answer 8

yep they are

Answer 9

yayy we were right :D
Thanks so much \(^-^)/

Answer 10

@razor99

can you explain this part
dr/dt = K / ((4(pi)r^2) = C / r^2
well the C part

Answer 11

well um i am not godd at that one :(

Answer 12

*good

Answer 13

did you mean k instead of C ??
for the bottom????
dr/dt = K / ((4(pi)r^2) = C / r^2

Answer 14

@razor99

Answer 15

um yes

Answer 16

thnx

Answer 17

no problem

Answer 18

dr/dt = K / (4(pi)r^2) = C / r^2
K, 4, pi are all constants and can be grouped together as another constant C.
C = K / (4(pi))