Question

Y>x^2 +2x -4
Y>x^2 -4x -1
(These are parabolas!) i need to solve, graph, and shade the parabolas! Please help!

Answer 1

@phi

Answer 2

@Hero

Answer 3

@jim_thompson5910

Answer 4

to graph y >x^2 +2x -4, you need to graph y = x^2 +2x -4 first

Answer 5

to graph y = x^2 + 2x - 4, you plot a series of points to get a rough idea of what it's shape is, then you draw a curve (your best guess) through them all

Answer 6

How do i get the points?

Answer 7

To get any point, you plug in a number for x to get corresponding value for y.

For example, let's say x = 0

y = x^2 + 2x - 4

y = (0)^2 + 2(0) - 4 ... replace x with 0 (since x = 0)

y = 0 + 2(0) - 4

y = 0 + 0 - 4

y = -4

So when x = 0, y = -4 giving us the point (0,-4)


So that means the point (0,-4) is on the graph of y = x^2 + 2x - 4

Answer 8

To get other points, you use other values for x (say x = 1, x = 2, etc)

Answer 9

Is threesome formula for finding the vertex?

Answer 10

yes

Answer 11

Is there*

Answer 12

x = -b/(2a) is the axis of symmetry formula

Answer 13

Ok, so use that formula to be the vertex,

Answer 14

yes, the axis of symmetry is the x coordinate of the vertex

Answer 15

Then i use other numbers to plug into the equation?

Answer 16

once you know the x coordinate of the vertex, you plug it back into the original equation to find the y coordinate of the vertex

Answer 17

And i have to shade

Answer 18

Where we pic a test point

Answer 19

after you graph the parabola for y = x^2 + 2x - 4

you shade based on what the inequality sign is

Answer 20

In the case of Y>x^2 +2x -4, we shade above the curve because we have a greater than sign

Answer 21

if the sign was <, you'd shade below the curve

Answer 22

But what if the y is <

Answer 23

then you shade below

Answer 24

Imconfuseh

Answer 25

you could use the test point method, but this way is faster

Answer 26

Actually i goit thanks

Answer 27

yw