Question

if (3,-y) is equidistant rom (3,6) and (7,2) then what is y?

Answer 1

Use the Distance Formula.\[d = \sqrt{\left( x _{2}-x _{1} \right)^2 - \left({y _{2} - y_{1}} \right)^2}\]

Answer 2

teach me step by step please i dont get it :(

Answer 3

You find the distance between (3,6) and (7,2), then divide that by 2 for d and use this d to find the distance between either (3,6) and (3,-y) or (3,-y) and (7,2).

Or, you could use the Midpoint Formula, if you want.\[m = \left(\frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2} \right)\]

Answer 4

use distance formula...
rt.or (x1-x2)^2+(y1-y2)^2
(3-3)^2+(6+y)^2=(3-7)^2+(2+y)2
sq rt can be removed by squaring both the side

Answer 5

ahh.. hard

Answer 6

Actually the distance formula doesn't work, and you need to try before you say it's too hard @jacalneaila \[d = \sqrt{(2-6)^2 + (7-3)^2} = \sqrt{16 + 16} \approx 5.66\]Midpoint Formula it is, then. \[m = \left( \frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2 } \right) = \left( \frac{ 3+7 }{ 2 }, \frac{ 6+2 }{ 2 } \right)\]Can you figure out the rest?

Answer 7

that solutio??n

Answer 8

It's part of it.

Answer 9

where the y??

Answer 10

y=8

Answer 11

.-. m = (x,y)

Answer 12

@adilalvi give her a chance to work it out herself

Answer 13

ok

Answer 14

how

Answer 15

\[m = \left( \frac{ 10 }{ 2 }, \frac{ 8 }{ 2 } \right) = \left( 5, 4 \right)\]Find the distance between (5,4) and one of the original given points, then use that to find the y value

Answer 16

-y+6+2=0
-y+8=0
y=8

Answer 17

I've already listed out the Distance Formula for you, so work it out yourself and I'll tell you whether you got it right or not.

Answer 18

further simplifing through distance formula
36+12y+y^2=16+4y++4+y^2
y^2 can be cancelled out from both the sides.
36+12y=20+4y
16=-8y
y=-2

Answer 19

huh..going crazy right now i dnt understand

Answer 20

-sigh- Hold on, I'll type it out for you.

Answer 21

what? O.o

Answer 22

I just realized I did the Distance Formula wrong in the first part lol\[\sqrt{(2-4)^2 - (7-5)^2} = \sqrt{4-4} = 0 \]Hmm.. that's strange.

Answer 23

You know it would be better if you graphed it out before solving.

Answer 24

what O.o

Answer 25

Graph it out.

Answer 26

Honestly I think @nirmalnema is right, but I just wanna check .-.

Answer 27

help please :(

Answer 28

@jacalneaila you ask what is not clear to you.?

Answer 29

all :(

Answer 30

teach me step by step

Answer 31

(3,-y) is equidistant rom (3,6) and (7,2) then what is y?
x1=3 , 7
x2=3
y1=2 , 6
y2= it is unknown.. you have to find it...

Answer 32

how?

Answer 33

Ask @AllTehMaffs :p

Answer 34

just consider it so that you can easily put the values in distance formula

Answer 35

how teach me please for my exam tommorow

Answer 36

(for reference)


So do you know what equidistant means?

Answer 37

(the unknown point is not correct in that drawing)

Answer 38

@jacalneaila ? Do you know what "equidistant" means?

Answer 39

nop

Answer 40

"equidistant" means "equal in distance"

So saying (3,-y) is "equidistant" from (3.6) and (7,2) means that the distance between (3,-y) and (3,6) is the same as the distance between (3,-y) and (7,2).

Does that make sense?

Answer 41

So the line segment that connects points (3,-y) and (3,6) is the same length as the line segment that connects points (3,-y) and (7,2).

Answer 42

Do you know what (3,6) means?

Can you plot (3,6) on a graph?

Answer 43

huh.. im going crazy right now