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in a triangle ABC angle A=40 and angle B=57 and side c is 30 cm find angle C
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i got the angle C its 83
find the length of a and b
@ALLTehMaffs
law of sines \[\frac{a}{\sin A} = \frac{c}{\sin C}\] \[\frac{b}{\sin B} = \frac{c}{\sin C}\]
a=19.47 b=25.41
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correct?
I got b=25.35 , which is really close so I dunno what's up
how about a?
that one I got the same
er, I got 19.43
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find the area of the triangle?
what?
i dnt understand
I did it wrong, 1 sec.
herons law?
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are you there?
Area of triangle = 1/2 (Base)(Height) = (1/2) (c)(h) |dw:1384438699375:dw| Make right triangle with b as hypotenuse to find the height, h SORRY \[h=b \cos A\] \[Area=\frac{1}{2}ch\] \[ = \frac{1}{2}c(b \cos A)\]
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