anyone help please please What is the direction of the net force that acts on an object undergoing uniform circular motion?
can u think and tell me why is there a net force required ? why is force required to keep an object in uniform circular motion? certainly for a uniform straight line motion, there is no net force required
look a force is needed to change the direction or magnitude or both of velocity of an object(change in velocity is only change in motion) in uniform circular motion, the direction of motion is continuously changing but magnitude is constant to change the magnitude of velocity of an object in motion, the force needs to be in the direction of the motion of the object. here the magnitude is constant so the force must be in the perpendicular direction to the motion (as forces in perpendicular direction to the motion can only change the direction of motion and not the magnitude). and direction of motion is nothing but the direction of velocity. so the total force is perpendicular to the velocity now imagine that the force is pointed towards the centre. if it is always pointed towards the centre of the the circle in which the object is performing circular motion, then only the circular motion would be possibe or if the force would point to any othe direction , circular motion would not be possible so the net force is directed towards the centre of the circle on which the object is performing circular motion.
this is a bit i mean a lot confusing so if you don't understand a thing, feel free to ask
dam thanks dude thank uit help a lot u really know what ur doing dont u huh.
you're welcome man
hey do u know the answere to this huh rajat97 What is one of Kepler's laws of planetary motion?
can u give me medal plz
thanks rajat97
hey do u know the answere to this huh rajat97 What is one of Kepler's laws of planetary motion?
Kepler's laws are: 1.The orbit of every planet is an ellipse with the Sun at one of the two foci. 2.A line joining a planet and the Sun sweeps out equal areas during equal intervals of time. 3.The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit. HOPE THIS HELPED!! :D
thank you jacaira
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