Question

the two sides of the triangle are 34 cm and 43 cm , if the included angle is 50 degree. Find the perimeter of the triangle?

Answer 1

let the third side is x, use the cosine rule to get x.

x^2 = 34^2 + 43^2 - 2(34)(43)cos50
solve for x, first

Answer 2

@RadEn then next step

Answer 3

after you get x, then the perimeter is sum all sides
perimeter = 34+43+x

what's x do you get ?

Answer 4

x^2 or x?

Answer 5

after you get x^2, take the squareroot to get x

Answer 6

33.55

Answer 7

correct?

Answer 8

i got different like yours

Answer 9

x^2 = 34^2 + 43^2 - 2(34)(43)cos50
x^2 = 1156 + 1849 - 2924(cos50)
x^2 = 3005 - 2924 * (0.64)
x^2 = 3005 - 1871.36
x^2 = 1133.64
x = 33.55

yeah, you are right, LOL

Answer 10

@RadEn find the length of the smallest altitude of the triangle

Answer 11

@RadEn

Answer 12

help please @RadEn

Answer 13

still in the figure no. 1 ?

Answer 14

\[34+43+\sqrt{1156 +1849 - 2924 \text{ Cos}[50{}^{\circ}]}=110.548 \]