Is anyone good at Point-Slope form, and stuff like that?
i am! what do you need help with?
Ok, for some reason my dumb brain wont comprehend how to do some parts of it. Can you try to explain how to do them to me? I'll send you an example problem. :)
to find a parallel line to a line you already know the slope of, it is easy. the slope stays the same for the new parallel line. for this one, the slope is -3. you have to use the slope, -3, and the given ordered pair, (-5,9). plug the slope and the point into the point slope form equation: \[y-y _{1}=mx(x-x _{1})\] m=-3 y1=9 x1=-5 plug it in and i will tell you if you got it correct.
y - 9 = -3 (x - -5)?
yes that is point slope, but you are looking for slope intercept, so distribute and add to get this equation: \[y=mx+b\]
y-x=2 ? or y-3x=6 @Niall
Umm y - 3x = 6?
Okay, so y - 9 = -3 (x - -5) would be y - 9 = -3x + 15 y = -3x + 24? @esshotwired
these are the steps: y-9=-3(x+5) y-9=-3x-15 y=-3x-24 for your answer above, the only thing wrong is it should be -24 and -15 because before you distribute, 2 negatives equal a positive
Ok. Do you do anything after that?
We can start from the beginning. What is the slope of the given line: y = -3x + 6 ?
nope thats it!
y - 9 = -3x - 15 y = -3x - 15 + 9 y = -3x - 6 is the answer.
oh yeah. i saw your answer before and thought 24, but it is -6. so it is y=-3x-6. @ranga reminded me
The quickest way to do this problem is to notice that a line parallel to the given line and passing through the point (-5,9) shifts the line to the left by 4 units as can be seen on the graph. Shifting left by 4 units means replacing x by (x+4) in the original function y = -3x + 6 y = -3(x+4) + 6 = -3x - 12 + 6 = -3x - 6
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