Question

Giving medals
solve 2x-5/x+4x-1/x+2=-3x+8/x^2+2x
a. -1+-radical433/12
b. 2, -3/2
c. -2/9
d. -2/3, 1/2

Answer 1

do u mean this?
2x-(5/x)+4x-(1/x)+2=-3x+(8/x^2)+2x

Answer 2

@DemolisionWolf

Answer 3

yikes, haha

Answer 4

do you know how to do it?!

Answer 5

I can help, yes.
first thing is we want to clear the fractions,
look for a polynomial we can multiply both sides by that can clear the fractions

Answer 6

x+2

Answer 7

that was my first pick aswell ^_^
that would clear the fractions on the left hand side, but not the fraction on the right hand side. so, we have to use (x^2+2x) and multiply it to both sides

Answer 8

can you show me?! lol

Answer 9

ya, 1 sec then...

Answer 10

so on the right we have:
\[\frac{ 3x+8 }{ x^2+2x } * (x^2+2x) \rightarrow 3x+8\]


'[\frac{ 3x+8 }{ x^2+2x } * (x^2+2x) \rightarrow 3x+8\]

Answer 11

the first term on the left would look like this:

\[\frac{ 2x-5 }{ x }*(x^2+2x)\rightarrow (2x-5)(x+2)\]



'[\frac{ 2x-5 }{ x }*(x^2+2x)\rightarrow (2x-5)(x+2)\]

Answer 12

wait so is it C?

Answer 13

do you wanna try the second term on the left?

\[\frac{ 4x-1 }{ x+2 }*(x^2+2x)\rightarrow ?\]

Answer 14

are you over working this problem out? it is kinda long if i'm going to show you each step...

Answer 15

sorta. what do you think it is?! lol

Answer 16

I get that way too...
what do I think it is.... I think it will have 2 solutions.
have you plugged in any of the solutions to see if the statment is true?

Answer 17

D?

Answer 18

haha, idk!
we can work it out some more together if u want tho...
ur choice

Answer 19

PLEASE!! lol i need help

Answer 20

did you not solve it all the way yet?!

Answer 21

no, not yet

Answer 22

here, you do this part
\[\frac {4x−1}{x+2}∗(x^2+2x)\rightarrow?\]


'[\frac {4x−1}{x+2}∗(x^2+2x)\rightarrow?\]

Answer 23

or is it easier if I write it this way:

\[(4x−1)* \frac {x^2+2x}{x+2}\rightarrow?\]

Answer 24

wait i got 4x-1.... lol