Question

a 125 sample of iron at 92.3 degree C is added into 50.0 g water at 27.7 degree C. That is the final temperature. specific heat of iron= 0.444 J*g^-1* C^-1 and specific heat of water = 4.184 J*g^-1*C^-1

Answer 1

a 125 sample of iron at 92.3 degree C is added into 50.0 g water at 27.7 degree C. WHAT is the final temperature. specific heat of iron= 0.444 J*g^-1* C^-1 and specific heat of water = 4.184 J*g^-1*C^-1