What is the difference of three and seven over eight minus one and three over four in simplest form? two and one over eight two and one over two 3 2
\[\left(3 + \frac{7}{8}\right) - \left(1 + \frac{3}{4}\right)\]
This is what you have to begin with
kk
aha
Keep in mind that you can distribute the negative and remove the parentheses: \[3 + \dfrac{7}{8} - 1 -\dfrac{3}{4}\]
yep
Afterwards you can pair the whole numbers together and the fractions together
okay
\[3 - 1 + \dfrac{7}{8} - \dfrac{3}{4}\]
You know what 3 - 1 is
ok
yes
3 - 1 = 2 so you have \[2 + \dfrac{7}{8} - \dfrac{3}{4}\]
yess
:)
Now try to figure out what \(\dfrac{7}{8} - \dfrac{3}{4}\) equals
8-4=4 7-3=4 4/4 = 1 whole
We don't subtract fractions like that
okay
We can only subtract fractions properly if they have the same denominator
so i simplify
You have to learn how to subtract fractions first before attempting this problem.
hello @WHAT?!
31/8 − 7/4
YES THAT IS WHAT I DID
ok
31/8 − 7/4 = ((31 × 4) − (7 × 8)) / (8 × 4) = (124 - 56) / 32 = 68/32 = 17/8 = 2 1/8
okay
@carolinagb02, you know how to do that but you don't know how to do \(\dfrac{7}{8} - \dfrac{3}{4}\)
@WHAT?!
ARE YOU THERE?
7/8 − 3/4 = ((7 × 4) − (3 × 8)) / (8 × 4) = (28 - 24) / 32 = 4/32 = 1/8
@Hero , please don't do that
just \[\frac{Log4}{Log8}\]
can you help?
@angel12310 what does that mean?
what does what mean?
what does the list mean?
@WHAT?! please do not post your question in someone else's question
okay guys, lets make something clear, I AM 11 YRS OLD NOT 22!
i don't understand certain things
plz guys don't leave!
i'm 11 too
@carolinagb02, you think you need to be 22 in order to understand how to do \[\dfrac{7}{8} - \dfrac{3}{4}\]
7/8 − 3/4 = ((7 × 4) − (3 × 8)) / (8 × 4) = (28 - 24) / 32 = 4/32 = 1/8
No, she thinks you have to be 22 to do\[\frac{ \log4 }{ \log8 }\]
thats wierd
0.66666666666
@carolinagb02 anymore questions??
@angel12310 \[\frac{7}{8} - \frac{3}{4} \\= \frac{7}{8} - \frac{3}{4} \times \dfrac{2}{2} \\=\frac{7}{8} - \frac{6}{8}\\=\frac{1}{8}\]
I just wanted 1 answer!
but I get a bunch of tests ;( and I came here for 1 simple answer
Well, take Hero's word for it. I'm sure he's far more educated than all of us.
Of course there's only one answer, but you have to understand how to get that answer.
Subtracting the fraction is only part of the solution.
Besides, OpenStudy isn't here to do your work for you, it's to show you how to do it so you can do it yourself later, when you can't ask other people for help. Like if you're taking a test or a quiz.
can someone give me that one answer I HAVE BEEN HERE FOR 33 MINUTES ON THE SAME QUESTION!!!!!!! it is frustrating
If we put all the steps together, we get: \[\left(3 + \frac{7}{8}\right) - \left(1 + \frac{3}{4}\right)\] \[3 - 1 + \dfrac{7}{8} - \dfrac{3}{4}\] \[2 + \frac{1}{8}\]
@carolinagb02 you got stuck after I asked you to subtract the fractions.
I know but... YOU KNOW WHAT! WHATEVER I CANT FIND ONE DUMB QUESTION I QUIT OPENSTUDY AND IT IS ALL OF UR PPL'S FAULT!
Don't get frustrated. Just review how to add and subtract fractions and you'll be fine.
I JUST WANTED TO FIGURE SOMETHING OUT AND ALL I GOT WAS A TOTAL DISSAPOINTMENT!
I quit this job
@carolinagb02, it is impossible to master adding and subtracting mixed fractions until you have mastered adding and subtracting regular fractions.
someone PLEASE! give me and answer and stop criticizing me!
You cannot do this: \[\left(3 + \frac{7}{8}\right) - \left(1 + \frac{3}{4}\right)\] Before knowing how to do this: \[\frac{7}{8} - \frac{3}{4}\]
and if u think ur not well you are! it is mean, unkind, disrespectful and annoying, P.S it shames the person!
you see! you just highlight peoples weaknesses!
@Hero this is why im not ur fan!
i gave the answer to you
31/8 − 7/4 = ((31 × 4) − (7 × 8)) / (8 × 4) = (124 - 56) / 32 = 68/32 = 17/8 = 2 1/8
7/8 − 3/4 = ((7 × 4) − (3 × 8)) / (8 × 4) = (28 - 24) / 32 = 4/32 = 1/8
@angel12310 , 2 1/8 can easily be confused with 21/8 It is not a good notation to use. 2 + 1/8 is the correct notation
what is a,b,c,and d
the 1st answer, the 2nd one the 3rd etc it goes by letter!
@carolinagb02, I know you are frustrated, but I cannot allow you to just simply ask for the answer. That's not how OS works
@Hero , how are you a moderator?
@carolinagb02, I understand that you are frustrated. Questioning my position as moderator really is not the issue.
he is smarter you should ask him if it's A.,B.,C.,or D.
I know, I just don't know if your a moderator because you have a 99 on ur status, I am not being rude, I just want to know how,
he is smart and very helpful that's why?
okay, cool
@carolinagb02, re-post the question. I will post the complete steps one last time.
no, I have a different one, do you know wich one it is?
ok
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