How do I find N?
\[16.13=12(1.03)^{n}\]
16.13=12(1.03)n 16.13=12*1.03n Then u divide: 12.36 from both sides. 16.13/12.36 = n 1.305 = n Im not sure, but I think is like that. Hope it helps...
Thanks.
\(\bf 16.13=12(1.03)^n\implies \cfrac{16.13}{12}=1.03^n\\ \quad \\ \textit{log cancellation rule of }\quad \color{blue}{log_aa^x=x}\qquad thus\\ \quad \\ \cfrac{16.13}{12}=1.03^n\implies log_{1.03}\left(\cfrac{16.13}{12}\right)=log_{1.03}(1.03^n)\\ \quad \\\implies log_{1.03}\left(\cfrac{16.13}{12}\right) = n\)
0.0
well... do you know the log rules? and the change of base rule?
you'd split the rational in 2 log sets, and then apply the change of base rule to each, to use either log base10 or natural log, ln
No, I do not know the LOG Rules. I know the Properties of Exponenents...I am only in ninth grade...
So the asnwe is 5.16?
@jdoe0001
hmmm.
well... makes me wonder why you're given....this exercise, maybe you weren't supposed to use logarithms.
Oh hold on this is the original thingie: A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the plant f(n), in cm, after n days. f(n) = 12(1.03)n Part A: When the scientist concluded his study, the height of the plant was approximately 16.13 cm. What is a reasonable domain to plot the growth function? (4 points)
@jdoe0001
hmmm then "n" is not an exponent, just a variable... so @lauluisa was correct
The n is an exponent.
It is just that copying and pasting does not show it.
... ok... well... since you haven't cover logarithms... yet... what you can do is graph it
so go over the y-axis up to 16.13 more or less, and see what "x" or domain, is at that point
you can zoom in/out by using the mouse middle-button btw
So it's about ten days...
yeap
Thanks.
yw
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