This question was on SAT, and no joke, it needs clarification, to me it looks just invalid!!

3. If x and y are integers, and 3x + 2y = 13, which of the following could be the value of y ?

Question

This question was on SAT, and no joke, it needs clarification, to me it looks just invalid!!

3. If x and y are integers, and 3x + 2y = 13, which of the following could be the value of y ?

anonymous · Answer

$$0$$$$1$$$$2$$$$3$$$$4$$

anonymous · Answer

I know it is no zero, right?

jdoe0001 · Answer

I'd solve for "y" first, and then plug in the values and solve for "x", see if which one gives you an integer

anonymous · Answer

$$y=-2/3x+13/3$$
@jdoe0001, ty, I think if I think, I'll get it...

anonymous · Answer

1

anonymous · Answer

Right?

anonymous · Answer

b/c for other values it is not an integer.

anonymous · Answer

TY!

jdoe0001 · Answer

$\bf 3x+2y=13\implies y = \cfrac{13-3x}{2}$

jdoe0001 · Answer

so... you'd test say... 0 , if y = 0, then $\bf 0 = \cfrac{13-3x}{2}\implies x=\cfrac{13}{3}  $ so no dice on 0

jdoe0001 · Answer

so checking on y = 1 then ... $\bf 1 = \cfrac{13-3x}{2}\implies 3x+2=13\implies x=\cfrac{11}{3}$   so no dice on 1 either

jdoe0001 · Answer

and so on :)

anonymous · Answer

So this SAT question would take at least about 6 minutes.
That's not a good time per question on the SAT.

amistre64 · Answer

instead of solving for y; solve for x .. they give you options in terms of y

amistre64 · Answer

3x + 2y = 13

$$x = \frac{-2y+13}{3}$$

which value of y  makes 13-2y a multiple of 3?

amistre64 · Answer

13
11
9
7
5

amistre64 · Answer

takes less then 30 seconds for me