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Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 5(x + 6)2(x - 6)3
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Is that\[f(x) = 5(x+6)^2(x-6)^3\]?
yes
set y = 0, thus \(\bf f(x) = 5(x + 6)^2(x - 6)^3\implies 0=5(x + 6)^2(x - 6)^3\) so... what are the zeros?
-6 and 6?
yeap
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soo -6 would have multiplicity of 3? and 6 of 2? wait is 4 a zero too?
the multiplicity it's just \(\bf 0=5(x + 6)^\color{blue}{2}(x - 6)^\color{red}{3}\implies 0=5\color{blue}{(x + 6)(x + 6)}\color{red}{(x - 6)(x - 6)(x - 6)}\)
okay so no 4
yes, the multiplicity, or the times they REPEAT is 2 and 3 respectively
thankyou :)
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yw
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