the function y=-0.296x^2+2.7x models the length x and height y that your sisters rabbit can jump in centimeters. how high does the rabbit jump? what is the length of the jump?
Ok, do you have a graphing calculator?
yup ^_^ who doesnt?
do you have an internet connection? http://www.wolframalpha.com/input/?i=y%3D-1.26%2B2.7x
Wrong equation bud.
bibbeh did u realy just ask me that?
I copied it letter for letter. you have to mess with the parentheses
I am trying to figure out how to do this algebraically again. I know how to do it with calculus easily! And there is an x^2 bibsy.
woah what. I literally copied y=-0.296x^2+2.7x into wolfram. Technology has betrayed me. Go forth austin
Okay, okay I think I got this. We can use the formula, \(\displaystyle x=\frac{-b}{2a}\) When we have, \(y=-ax^2+bx\) Then we can plug it back into the original equation and solve for y. That will be your maximum value. Make sense?
so i have to move the b and a over?
No, they are literally given to you in your initial problem. Look at the general form that I posted and look at your equation. Don't they look similar? a&b are merely coefficients.
sorry this is not making any sense to me whatsoever..its just one of those days
\(y=\color{red}{-0.296}x^2+\color{blue}{2.7}x\) \(y=\color{red}{-a}x^2+\color{blue}{b}x\)
oh yea i understood that part
Okay, now plug that into the little formula that I gave you.
\[x= \frac{ -2.7 }{ -0.296 }\]
x=-b/(2a)
whoops i forgot to multiply the denominator by 2
so it would be \[x=\frac{ -2.7 }{2(-0.296) }\]
Excuse me, I believe I made an error.... Maximum value is, \(\displaystyle max=c-\frac{b^2}{4a}\) Where, \(y=-ax^2+bx+c\) In our case, c=0 Sorry about that :(
so pretty much i would just have to square the b and instead of multiplyin a by 2 it would b 4?
Yeah, sorry again.
its ok :D let me work this out rite quick
-6.15?
oh wait no its not negative so it would just b 6.15?
That is what I get, but remember it is -(-6.15), so 6.15
Beat me to it :P
Then to find the distance, you would just find the x intercepts. The zeros.
how do i do that|?
I believe you could use the quadratic formula. I will brb, try that and I will check back shortly.
ok
wait would i need to just find the vertex?
or did we already do that?
That was how high, we want to know how far now.
oh 9.14 cm?
For some reason I keep getting zero.... But on my calculator is giving me 9.12162
ehh about the same thanks austin ^_^
No problem! Good job btw!
Oh, the repugnant smell of uncertainty... I detect a hint of it here :>
Shhhh @terenzreignz I corrected course......
When did I ever doubt you? :D
tj is that u?
Let me check...
<looks around> Yup, I'm pretty sure my name is TJ, one way or another, since those two letters adorn quite a few select nooks in my room :>
oh tj :P
Join our real-time social learning platform and learn together with your friends!