Question

how would i solve rational exponent (y2/3)-9

Answer 1

\(\bf \large{(a^n)^m\implies a^{n\cdot m}\qquad thus\\ \quad \\
\left(y^{\frac{2}{3}}\right)^{-9}\implies y^{\frac{2}{3}\cdot -9}}\)

Answer 2

ok i got that part

Answer 3

i would get y-18/3

Answer 4

\(\bf \large{ (a^n)^m\implies a^{n\cdot m}\qquad thus\\ \quad \\
\left(y^{\frac{2}{3}}\right)^{-9}\implies y^{\frac{2}{3}\cdot -9}\implies y^{-\frac{18}{3}}\implies y^{-6}}\)

Answer 5

do i simplify that and if so how would i write it

Answer 6

\(\bf a^{-n} = \cfrac{1}{a^n}\qquad thus\\ \quad \\
y^{-6}\implies \cfrac{1}{y^6}\)

Answer 7

thats all i dont have to write a radical?

Answer 8

well, you didn't get a fraction in the exponent, so no radical, if it was ... say 1/2 or 5/6 then you'd end up with a root, but in this case you only have a "6"

Answer 9

ok