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can you find the domain of ln(1-2x)/sqrt(3-x) please!
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Since the expression is divided by a square root, the (3-x) cannot be zero and negative. Cannot be zero because you cant divide by zero and cannot be negative cause there is no value for square root of a negative number. So 3-x>0, therefore x < 3. Therefore the domain of the function is (-infinity,3).
Thank you so much
\[\log_{b} 3=.978 and \log_{b} 5= 1.61, find \log_{b} 3b and \log_{b} 75\]
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